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I'm in the process of making a Serious Game for a class I have, and I'm trying to display a box or a panel when I click one of the 4 GUI buttons. What would be the easiest way to make a panel be displayed when a certain button is clicked? Also, could I have 4 different panels? For example, if I click one button, Panel A shows up. If I click another button, Panel B shows up. Is that possible?

Answer 1

0

It's possible and there is many ways to do it. You could have everything in one script and display the correct panel depending on an enum

public enum PanelType{ Apple, Banana, Orange, None }

// class, OnGUI ans stuff ...

if( GUI.Button(...) ) type = PanelType.Apple;

//...

if( type == PanelType.Apple ) DisplayApplePanel();
else ...

Or you could use a separate script for the pannels and enable the one you need

public MyPannel one, two, three, four;

// ...

if( GUI.Button(...) ) // Disable last one and enable new one

answered May 18 '12 at 04:58 PM

Berenger
11k ● 12 ● 19 ● 53

UnityGUI (this is the name of what's happening in OnGUI()) takes care of how it is displayed. You need to attach a script to a gameobject that implement the function OnGUI. Inside, you need can call GUI.Label, Button, Box etc. That gameObject doesn't need a mesh or anything else.

Could use comments instead of answer please ?

May 18 '12 at 07:43 PM Berenger

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Answer 2

0

So essentially I will have to create 4 panels or planes and name them accordingly, correct?

answered May 18 '12 at 05:07 PM

CornDog3241
0 ● 1 ● 2 ● 4

(comments are locked)

Answer 3

0

Bare with me, I'm not a very strong programmer or scripter :/ haha

answered May 18 '12 at 05:50 PM

CornDog3241
0 ● 1 ● 2 ● 4

(comments are locked)

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Displaying a panel on GUI click

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