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Hi

I've made this work on a character currently in my scene, but I just can't get it to work on the newest character I have added.

Here is the scripting I have been using

function Start () { animation["machineGunShoot"].layer = 14; animation["laserShoot"].layer = 14;

var mixShootLaserGun : Transform = transform.Find("waistM/back1M/back2M/RclavicleM/RshoulderM/RelbowM/RwristM/Rcannon1M");

animation["laserShoot"].AddMixingTransform(mixShootLaserGun);

var mixMachineGun : Transform = transform.Find("waist/back1/back2/Lclavicle/Lshoulder");

animation["machineGunShoot"].AddMixingTransform(mixMachineGun);

}

function Update () { if (Input.GetAxis("R_Trigger") > 0.1 && animation.IsPlaying("idle"))

    animation.Play("laserShoot");

}

Can anyone see any problems with what I have done? Or help me understand why it isn't working?

Thanks

Answer 1

0

Not sure if this is related, but whenever I set AnimationState.layer to anything other than the default (0), I get a null reference exception.

Try removing the part where you change the 'animation["animName"].layer' at the start and see if the exception goes away.

answered May 12 '12 at 06:37 PM

Moj
0 ● 1 ● 1 ● 2

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Answer 2

0

I think you missed some ( and ).

Try with that :

function Update () { if ((Input.GetAxis("R_Trigger") > 0.1) && (animation.IsPlaying("idle")))

    animation.Play("laserShoot");
}

answered Apr 08 '12 at 10:48 PM

DJSwiti
105 ● 6 ● 8 ● 9

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Answer 3

0

The code you're using before the Update function never gets used because you're just playing your standard lasershoot animation. add Debug.Log("Laser Shooting"); before the animation.play("laserShoot"); to see if the if statement is executed.

answered Apr 07 '12 at 09:13 AM

garner
120 ● 1

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Answer 4

0

I just tried that, and the animation is playing. It just isn't isolating the bones I want to play the animation on :/

It should work, because I used the same code for a character in the same game (obviously defining different bones) I just don't understand why it will work for one character and not for another!

answered Apr 07 '12 at 03:30 PM

Joevis
1 ● 9 ● 13 ● 13

These can be easier to read if you put short replies to someone as a comment on theirs.

Apr 07 '12 at 04:19 PM Owen Reynolds

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Add Mixing Transform Doesn't Work!!

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